Ex3 Basic principles semiconductors

I have a question about this exercise. I was making it and using the expression Eh=-E relating the electron energy and the hole energy of the same band. And the Hamilton equations for the group velocity and the effective mass I kept deriving ve=-vh and me*=-mh* . However this does not make sense as a semi conductor is neutral in charge giving me a net current when a field is applied. Thus when making the exercise I noticed that the velocity in the same band should be of the same sign as the charges of holes and electrons are opposite sign. So I made up that in reciprocal space the wave numbers(k) need to be opposite In sign kh=-k such that this problem is fixed. I put my derivation in the image.

Question:Is this how you’re supposed to do this?Because when you take kh=-k you do get the correct expressions.

Hi Kenichi,

Thanks for your question. Indeed, that approach is correct. If you check the lecture notes you can find that they arrive at the same conclusion.

If we have a full band and remove an electron with momentum k, the whole band has now only one unpaired electron with momentum -k, so that is the momentum of the hole. Since both energy and momentum have a negative sign and v=\frac{1}{\hbar}\frac{\partial E}{\partial k} you get that both have the same velocity.