Density of states using group velocity for phonons

Hi course,

For the first problem of the tight-binding model exercises I’ve used the relation E= \hbar \omega and basically substituted that into the expression for group velocity which reads:
v_g = \frac{1}{\hbar} \frac{\partial E}{\partial k} Then from this I got that for phonons we get:
v_g = \frac{1}{\hbar} \frac{\partial (\hbar \omega)}{\partial k}
so the \hbar cancels out and we’re left with v_g = \frac{\partial \omega}{\partial k}. Then I subbed this into the density of states as you can see in my attached picture but I keep getting an extra \hbar that isn’t there in the DOS. What’s going wrong here? (In the final expression there’s \hbar in the denominator)

Density of states is sometimes defined as # of state per unit of frequency, and sometimes per unit of energy. The difference between the two quantities is a factor of \hbar, so no problems here :heavy_check_mark:

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Heyah!

It is sometimes useful to start from the definitions of DOS: g\left(E\right) = \frac{dN}{dE} and g\left(\omega\right) = \frac{dN}{d\omega} with E = \hbar\omega :

g\left(\omega\right) = \frac{dN}{d\omega} = \frac{dN}{dE} \frac{dE}{d\omega} = g\left(E\right) \frac{dE}{d\omega} = g\left(E\right) \hbar
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