Density of states using group velocity for phonons

Hi course,

For the first problem of the tight-binding model exercises I’ve used the relation E= \hbar \omega and basically substituted that into the expression for group velocity which reads:
v_g = \frac{1}{\hbar} \frac{\partial E}{\partial k} Then from this I got that for phonons we get:
v_g = \frac{1}{\hbar} \frac{\partial (\hbar \omega)}{\partial k}
so the \hbar cancels out and we’re left with v_g = \frac{\partial \omega}{\partial k}. Then I subbed this into the density of states as you can see in my attached picture but I keep getting an extra \hbar that isn’t there in the DOS. What’s going wrong here? (In the final expression there’s \hbar in the denominator)
WhatsApp Image 2022-03-08 at 20.29.20

Density of states is sometimes defined as # of state per unit of frequency, and sometimes per unit of energy. The difference between the two quantities is a factor of \hbar, so no problems here :heavy_check_mark:

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Heyah!

It is sometimes useful to start from the definitions of DOS: g\left(E\right) = \frac{dN}{dE} and g\left(\omega\right) = \frac{dN}{d\omega} with E = \hbar\omega :

g\left(\omega\right) = \frac{dN}{d\omega} = \frac{dN}{dE} \frac{dE}{d\omega} = g\left(E\right) \frac{dE}{d\omega} = g\left(E\right) \hbar
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